Oracle 1z0-809 Q&A - in .pdf

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NEW QUESTION: 1
ある企業が、ヨーロッパのユーザーにモバイルアプリを提供しています。アプリを使用すると、デバイスとアプリのバージョン固有の構成ファイルがダウンロードされます。同社のアーキテクチャは次のとおりです。
*構成ファイルはeu-west-1リージョンのAmazon S3に保存され、Amazon CloudFrontを使用してユーザーに提供されます。
* Lambda @ Edgeは、アプリのリクエストからデバイスとバージョン情報を抽出するために使用されます。次に、要求を更新して正しい構成をロードします。
会社は構成ファイルの読み込み時間を主要なパフォーマンスメトリックとして使用し、
100ミリ秒以下。アプリは最近ap-southeast-2リージョンでリリースされ、オーストラリアのユーザーからのリクエストのレイテンシは100ミリ秒のターゲットを大幅に上回っています。ソリューションアーキテクトは、ソリューションを推奨する必要があります。
オーストラリアのユーザーの待ち時間を短縮するソリューションはどれですか?
A. バケットでS3 Transfer Accelerationを構成するLambdaEdgeを変更して、ユーザーに最も近いリージョンのTransfer Accelerationエンドポイントを使用してAmazon S3にアクセスします。
B. バケットでS3 Transfer Accelerationを構成しますCloudFrontオリジンとしてオーストラリアおよびヨーロッパのTransfer Acceleration Edgeエンドポイントを追加しますLambda @ Edgeを変更して、リクエストのオリジンをユーザーに最も近いリージョンのTransfer Accelerationエンドポイントに更新します
C. ap-southeast-2リージョンにS3バケットを作成します。クロスリージョンレプリケーションを使用してeo-west-1リージョンのバケットから同期し、ユーザーに最も近いReg> onでAmazon S3にアクセスするようにlambdeEdgeを変更します。
D. ap-southeast-2リージョンにS3バケットを作成します。クロスリージョンレプリケーションを使用して、eu-west-1リージョンのバケットから同期します。両方のバケットにレイテンシベースのルーティングが設定されたAmazon Route 53ホストゾーンを作成します。Lambda@ Edgeを変更して、リクエストの送信元を(he Routeユーザーに最も近いS3ホストゾーン
Answer: B

NEW QUESTION: 2
Your server administrator upgraded a Windows 2016 Server from 16 Gb to 32 Gb HBAs. The application owner is now reporting slower performance to the AFF A700.
Which two actions will help troubleshoot performance on the server? (Choose two.)
A. Verify the HBA model using Hardware Universe.
B. Confirm that Windows Host Utilities Is installed.
C. Verify the HBA firmware using the Interoperability Matrix Tool.
D. Confirm that LUN mapping exists.
Answer: A,C

NEW QUESTION: 3
When using unicast music on hold, how many streams will be sent to endpoints if a corporate marketing department has a customized message that is played whenever a customer is placed on hold?
A. one for each endpoint placed on hold
B. one
C. one per instance of music on hold in the server
D. one for each message in the music on hold system
Answer: A

NEW QUESTION: 4



A. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
B. CustNo IS NULL
C. CustNo
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT
CustNoFROM tblLoanAcct) R
E. CustNo = L.CustNo
F. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct
DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo
I. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
J. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT
AcctNoFROM tblLoanAcct) R
K. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
Answer: K
Explanation:
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp

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