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NEW QUESTION: 1
Which of the following statements is correct regarding URL Filtering on the FortiGate unit?
A. Multiple URL Filter lists can be added to a single Web filter profile.
B. A FortiGuard Web Filtering Override match will override a block action in the URL filter list.
C. The available actions for URL Filtering are Allow, Block and Exempt.
D. The available actions for URL Filtering are Allow and Block.
Answer: C

NEW QUESTION: 2

A. Option A
B. Option B
C. Option D
D. Option C
Answer: B,D

NEW QUESTION: 3
Azure Batchジョブを作成して実行するためのコードを書いています。
計算ノードのプールを作成しました。
バッチジョブをBatchサービスに送信するには、正しいクラスとそのメソッドを選択する必要があります。
どの方法を使うべきですか？
A. CloudJob.Enable（IEnumerable <BatchClientBehavior>）
B. JobOperations.EnableJobAsync（String。IEnumerable <BatchClientBehavior>。CancellationToken）
C. JobOperations.EnableJob（String、IEnumerable <BatchClientBehavior>）
D. JobOperations.CreateJobO
E. CloudJob.CommitAsync（IEnumerable <BatchClientBehavior>、CancellationToken）
Answer: E
Explanation:
Explanation
A Batch job is a logical grouping of one or more tasks. A job includes settings common to the tasks, such as priority and the pool to run tasks on. The app uses the BatchClient.JobOperations.CreateJob method to create a job on your pool.
The Commit method submits the job to the Batch service. Initially the job has no tasks.
{
CloudJob job = batchClient.JobOperations.CreateJob();
job.Id = JobId;
job.PoolInformation = new PoolInformation { PoolId = PoolId };
job.Commit();
}
References:
https://docs.microsoft.com/en-us/azure/batch/quick-run-dotnet

NEW QUESTION: 4
모바일 애플리케이션을 설계하는 회사에서 일하고 있습니다. 플레이어 레코드가 다른 게임에 할당 된 서버를 유지 관리합니다. 추적 시스템은 새롭고 개발 중입니다.
이 응용 프로그램은 Entity Framework를 사용하여 Azure 데이터베이스에 연결합니다. 데이터베이스에는 플레이어 테이블과 게임 테이블이 있습니다.
플레이어를 추가 할 때 코드는 새로운 플레이어 레코드를 삽입하고 기존 게임 레코드와 새 플레이어 레코드 사이의 관계를 추가해야 합니다.
응용 프로그램은 올바른 gameId 및 playerId를 사용하여 CreatePlayerWithGame을 호출하여 프로세스를 시작합니다.
(라인 번호는 참고 용으로 만 포함됩니다.)

다음 명령문 각각에 대해 명령문이 참이면 예를 선택하십시오. 그렇지 않으면 아니오를 선택하십시오.
참고 : 각각의 올바른 선택은 한 점으로 가치가 있습니다.

Answer:
Explanation:

Explanation:
Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
.HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Post)
.WithMany(p => p.PostTags)
.HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Tag)
.WithMany(t => t.PostTags)
.HasForeignKey(pt => pt.TagId);
}
}