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NEW QUESTION: 1
An IT organization already has a mixture of products that they are using for their application integrations. They want to map their products onto the service-oriented integration architecture. What guidance do you give them for accomplishing this task?
A. A product is compared to the Oracle products that are already mapped onto the architecture. The product is mapped onto the architecture as a replacement for the most similar Grade product,
B. The capabilities in a product are identified and then the product is mapped to the architecture based on those capabilities. A product can map to more than one layer of the architecture.
C. Products are not directly mapped onto the architecture; only the capabilities provided by the products are mapped onto the architecture.
D. The capabilities in a product are identified and then the product mapped to the architecture based on those capabilities. The product is mapped to the layer of the architecture where the most capabilities lie.
E. A product is compared to the Oracle products that are already mapped onto the architecture. If the product provides all the capabilities of an Oracle product, the product replaces that Oracle product.
Answer: B
Explanation:
Reference:http://www.oracle.com/technetwork/topics/entarch/oracle-ra-soa-infrastructurer3-2-1561710.pdf(page 40)

NEW QUESTION: 2
Ein Projektmanager überwacht und zeichnet die Ergebnisse der Ausführung der Qualitätsmanagementaktivitäten auf, um die Leistung zu bewerten und sicherzustellen, dass die Projektergebnisse vollständig und korrekt sind und den Kundenerwartungen entsprechen.
Welche Ausgabe verwendet der Projektmanager?
A. Arbeitsleistungsdaten
B. Genehmigte Änderungsanforderungen
C. Lektionen gelernt
D. Verifizierte Ergebnisse
Answer: D

NEW QUESTION: 3
Given:
ConcurrentMap <String, String> PartList = new ConcurrentMap<>();
Which fragment puts a key/value pair in partList without the responsibility of overwriting an existing key?
A. partList.putIfNotLocked (key,"Blue Shirt");
B. partList.putAtomic(key,"Blue Shirt")
C. if (!partList.containsKey(key)) partList.put (key,"Blue Shirt");
D. partList.out(key,"Blue Shirt");
E. partList.putIfAbsent(key,"Blue Shirt");
Answer: E
Explanation:
putIfAbsent(K key, V value)
If the specified key is not already associated with a value, associate it with the given value.
Reference:java.util.concurrent,Interface ConcurrentMap<K,V>