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NEW QUESTION: 1
展示を参照してください。

Link1は銅線接続で、Link2はファイバー接続です。ファイバポートは、すべての転送のプライマリポートである必要があります。 SW2でのshow spanning-treeコマンドの出力は、ファイバーポートがスパニングツリーによってブロックされていることを示しています。エンジニアがSW2のGO / 1でspanning-tree port-priority 32コマンドを入力しましたが、ポートはブロックされたままです。問題を解決するには、Link2に接続されているポートでどのコマンドを入力する必要がありますか？
A. SW1にスパニングツリーポートプライオリティ32を入力します。
B. SW1にスパニングツリーポートプライオリティ224を入力します。
C. SW2でスパニングツリーポートプライオリティ64を入力します。
D. SW2のスパニングツリーポートプライオリティ4を入力します。
Answer: A
Explanation:
Explanation
SW1 needs to block one of its ports to SW2 to avoid a bridging loop between the two switches.
Unfortunately, it blocked the fiber port Link2. But how does SW2 select its blocked port? Well, the answer is based on the BPDUs it receives from SW1. answer 'Enter spanning-tree port-priority 32 on SW1' BPDU is superior than another if it has:
1. answer 'Enter spanning-tree port-priority 32 on SW1' lower Root Bridge ID
2. answer 'Enter spanning-tree port-priority 32 on SW1' lower path cost to the Root
3. answer 'Enter spanning-tree port-priority 32 on SW1' lower Sending Bridge ID
4. answer 'Enter spanning-tree port-priority 32 on SW1' lower Sending Port ID These four parameters are examined in order. In this specific case, all the BPDUs sent by SW1 have the same Root Bridge ID, the same path cost to the Root and the same Sending Bridge ID.
The only parameter left to select the best one is the Sending Port ID (Port ID = port priority + port index). And the port index of Gi0/0 is lower than the port index of Gi0/1 so Link 1 has been chosen as the primary link.
Therefore we must change the port priority to change the primary link. The lower numerical value of port priority, the higher priority that port has. In other words, we must change the port-priority on Gi0/1 of SW1 (not on Gi0/1 of SW2) to a lower value than that of Gi0/0.

NEW QUESTION: 2
Sie entwickeln eine Microsoft SQL Server 2012-Datenbank für ein Unternehmen. Die Datenbank enthält eine Tabelle, die durch die folgende Transact-SQL-Anweisung definiert wird:

Mit dem folgenden Transact-SQL-Skript fügen Sie neue Mitarbeiterdaten in die Tabelle ein. Zeilennummern dienen nur als Referenz.

Wenn ein Fehler auftritt, müssen Sie die Fehlermeldung und die Zeilennummer, in der der Fehler aufgetreten ist, melden und die Verarbeitung der Fehler fortsetzen.
Sie müssen das Transact-SQL-Skript ausführen.
Welches Transact-SQL-Segment sollten Sie in Zeile 06 einfügen?
A. DECLARE @message NVARCHAR (1000), @ severity INT, @state INT;
SELECT @message = ERROR_MESSAGE (), @severity = ERROR_SEVERITY (), @state = ERROR_STATE (); THROW (@message, @severity, @state);
B. WURF;
C. DECLARE @message NVARCHAR (1000), @ severity INT, @state INT;
SELECT @message = ERROR_MESSAGE (), @severity = ERROR_SEVERITY (), @state = ERROR_STATE (); RAISERROR (@message, @severity, @state);
D. SELECT ERROR_LINE (), ERROR_MESSAGE ()
Answer: C
Explanation:
When the code in the CATCH block finishes, control passes to the statement immediately after the END CATCH statement. Errors trapped by a CATCH block are not returned to the calling application. If any part of the error information must be returned to the application, the code in the CATCH block must do so by using mechanisms such as SELECT result sets or the RAISERROR and PRINT statements.
Reference:
https://msdn.microsoft.com/en-us/library/ms175976.aspx

NEW QUESTION: 3
var firstName="Sandy" would be the correct way to declare the variable firstName and assign it an initial value of "Sandy".
A. True
B. False
Answer: A

NEW QUESTION: 4
An administrator needs to configure Acropolis File Service (AFS). The administrator is setting up AFS for the first time on the Nutanix cluster.
How many file services VMs are created by default?
A. 0
B. 1
C. 2
D. 3
Answer: C