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NEW QUESTION: 1
You want to modify a service profile that is bound to an updating template. Which description of the relationship between the service profile and the updating template is true?
A. The service profile is updated automatically when the updating template changes.
B. Change to the updating template apply only to service profile created after template after the template is updated.
C. The updating template can be changed only before the service profile is implemented
D. The service profile is updated after the server reboots.
Answer: C

NEW QUESTION: 2
Examine this query and output:
SQL> select order_flag, cache_size, session_flag, keep_value,
2 from user_sequences where sequence_name = 'SEQ1';
O CACHE_SIZE S K
-- ------------------- -- --
Y 10 N N
Performance analysis revealed severe SQ enqueue contention on the SEQ1 sequence.
The SEQ1 sequence is incremented from all instances equally and is frequently used.
Which two statements should you execute to reduce SQ enqueue contention?
A. alter sequence seq1 keep;
B. alter sequence seq1 noorder;
C. alter sequence seq1 cache 10000;
D. exec sys.dbms_shared_pool.keep ('SEQ1', 'Q')
E. alter sequence seq1 order;
Answer: C,D
Explanation:
A: Use cache.
D: The KEEP procedure keepsan object in the shared pool. Once an object has been kept in the shared pool, it is not subject to aging out of the pool. This may be useful for frequently used large objects. When large objects are brought into the shared pool, several objects may needto be aged out to create a contiguous area large enough.
References: https://ora600tom.wordpress.com/2015/01/09/enq-sq-contention/ https://docs.oracle.com/cd/B19306_01/appdev.102/b14258/d_shpool.htm#i999221

NEW QUESTION: 3
View the Exhibit and examine the structure of the PROMOSTIONS table:
Exhibit:

Which two SQL statements are valid? (Choose two.)
A. SELECT promo_id, DECODE (promo_cost, 10000,DECODE(promo_category, 'G1', promo_cost *.25, NULL),NULL) "Catcost"FROM promotions;
B. SELECT promo_id, DECODE (NVL(promo_cost, 0), promo_cost,promo_cost * 0.25,
100) "Discount"FROM promotions;
C. SELECT promo_id, DECODE (promo_cost, >10000, 'High',<10000, 'Low')
"Range"FROM promotions;
D. SELECT promo_id, DECODE (NULLIF(promo_cost, 10000),NULL, promo_cost*.25,
'N/A') "Catcost"FROM promotions;
Answer: A,B
Explanation:
The DECODE Function
Although its name sounds mysterious, this function is straightforward. The DECODE function implements ifthen-else conditional logic by testing its first two terms for equality and returns the third if they are equal and optionally returns another term if they are not.
The DECODE function takes at least three mandatory parameters, but can take many more. The syntax of the function is DECODE(expr1, comp1, iftrue1,
[comp2, iftrue2...[ compN, iftrueN]], [iffalse]).

NEW QUESTION: 4
다음 중 목표 반복, 세트 및 휴식 기간 중 MOST가 근력을 효과적으로 향상시키는 것은 어느 것입니까?
목표 반복으로 휴식 기간 설정
A. 5 4 1 분
B. 8 2 1 분
C. 8 4 1 분
D. 5 3 4 분
Answer: D