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NEW QUESTION: 1
DRAG DROP
You administer a Microsoft SQL Server 2012 database.
The database contains a schema named CUSTOMER. CUSTOMER contains several tables and views with sensitive data, as well as various stored procedures and functions.
In order to configure security for CUSTOMER, you need to determine how to meet the security requirements listed in the answer area.
Which command or commands should you use? (To answer, drag the appropriate command or commands to their corresponding security requirement or requirements in the answer area. Answer choices may be used once, more than once, or not at all. Answer targets may be used once or not at all. Additionally, you may need to drag the split bar between panes or scroll to view content.)

Answer:
Explanation:

NEW QUESTION: 2
An integrator needs to install Windows Server 2012 R2 on 6 HP ProLiant BL460C Gen9 servers. The servers will be part or an SQL cluster and must be configured identically. The integrator needs to use Intelligent Provisioning to complete this task.
What does Intelligent Provisioning use to allow the integrator to create deployment settings profiles to make this process more efficient?
A. iLO Federation Management
B. HP Smart Storage Administrator
C. HPSSACLI Utility
D. HP Insight Remote Support
Answer: B

NEW QUESTION: 3
무선 통신 링크를 사용하여 카메라와 수신기간에 이미지를 전송하는 CCTV (폐쇄 회로 텔레비전) 시스템을 배포 할 때 가장 고려해야 할 사항은 다음 중 무엇입니까?
A. 경비원에 의한 모니터링
B. 녹음 보존 기간
C. 카메라의 전략적 배치
D. 전송 암호화
Answer: D

NEW QUESTION: 4
View the Exhibit and examine the data in ORDERS and ORDER_ITEMS tables.
You need to create a view that displays the ORDER ID, ORDER_DATE, and the total number of
items in each order.
Which CREATE VIEW statement would create the view successfully?

A. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)| NO OF ITEMS'
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date
WITH CHECK OPTION;
B. CREATE OR REPLACE VIEW ord_vu (order_id,order_date)
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
C. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
D. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
Answer: D