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NEW QUESTION: 1
When a packet arrives at the gateway, the gateway checks it against the rules in the hop Policy Layer, sequentially from top to bottom, and enforces the first rule that matches a packet. Which of the following statements about the order of rule enforcement is true?
A. If the Action is Drop, the gateway continues to check rules in the next Policy Layer down.
B. If the Action is Accept, the gateway allows the packet to pass through the gateway.
C. If the Action is Drop, the gateway applies the Implicit Clean-up Rule for that Policy Layer.
D. If the Action is Accept, the gateway continues to check rules in the next Policy Layer down.
Answer: D

NEW QUESTION: 2
契約に関するどの情報を分析SAP Fioriアプリから直接取得できますか？ （2）
A. 低価格の契約
B. 未承認の契約
C. 契約満了
D. 未使用の契約
Answer: C,D

NEW QUESTION: 3
If you have a playbook task that errors out. where could you see the output of the task?
A. Demisto Audit log
B. Playbook Editor
C. /var/log/messages
D. War Room of the incident
Answer: B

NEW QUESTION: 4
あなたはモバイルアプリケーションを設計する会社で働いています。彼らは、プレーヤーの記録が異なるゲームに割り当てられるサーバーを維持しています。追跡システムは新しく、開発中です。
アプリケーションは、EntityFrameworkを使用してAzureデータベースに接続します。データベースには、PlayerテーブルとGameテーブルがあります。
プレーヤーを追加するとき、コードは新しいプレーヤーレコードを挿入し、既存のゲームレコードと新しいプレーヤーレコードの間に関係を追加する必要があります。
アプリケーションは、正しいgameIdとplayerIdを指定してCreatePlayerWithGameを呼び出し、プロセスを開始します。 （行番号は参照用にのみ含まれています。）

次の各ステートメントについて、ステートメントがtrueの場合は、[はい]を選択します。それ以外の場合は、[いいえ]を選択します。
注：正しい選択はそれぞれ1ポイントの価値があります。

Answer:
Explanation:

Explanation

Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Post)
WithMany(p => p.PostTags)
HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Tag)
WithMany(t => t.PostTags)
HasForeignKey(pt => pt.TagId);
}
}