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NEW QUESTION: 1
You are implementing ElGRP between the main office and branch offices. In Phase 1 you must implement and verify EIGRP configurations as mentioned in the topology in Phase 2. your colleague is expected to do NAT and ISP configurations Identity the issues that you are encountering during Phase 1 EIGRP implementation.
* Router R1 connects the main office to the Internet and routers R2 and R3 are internal routers
* Routers Branch 1 and Branch2 connect to router R2 in the main office.
* Users from the Branch1 LAN network 10 20 40 0724 are expected to perform testing of the application that is hosted on the servers in Server farm1, before servers are available for production
- The GRE tunnel is configured between R3 and Branch1, and traffic between server farm1 and Branch1 LAN network 10 20 40 0/24 is routed through the GRE tunnel using static routes
* The link between Branch1 and Branch2 is used as a secondary path in the event of failure of the primary path to mam office You have console access on R1. R2. R3. Branch1, and Branch2 devices Use only show commands to troubleshoot the issues Topology:




The traffic from Branch2 to the main office is using the secondary path instead of the primary path connected to R2. Which cause of the issue is true?
A. EIGRP packets were blocked by the inbound ACL on Branch2.
B. The network 192.163.11,0/30 was not advertised into EIGRP on Brancfi2.
C. The primary path has more link delay configured then secondary path which causes EIGRP to choose the secondary path.
D. The IP address was misconfigured between the Branch2 and R2 interfaces.
Answer: D

NEW QUESTION: 2

A. Option C
B. Option B
C. Option A
D. Option D
Answer: C
Explanation:
Scenario:
Mailbox databases that contain mailboxes for the New York office users must only be activated on the servers in the London office manually.
We can use the Suspend-MailboxDatabaseCopy cmdlet with the -ActivationOnly parameter.

NEW QUESTION: 3
Given the code fragment:
Map<Integer, String> books = new TreeMap<>();
books.put (1007, “A”);
books.put (1002, “C”);
books.put (1001, “B”);
books.put (1003, “B”);
System.out.println (books);
What is the result?
A. {1002 = C, 1003 = B, 1007 = A}
B. {1007 = A, 1001 = B, 1003 = B, 1002 = C}
C. {1007 = A, 1002 = C, 1001 = B, 1003 = B}
D. {1001 = B, 1002 = C, 1003 = B, 1007 = A}
Answer: D
Explanation:
Explanation/Reference:
Reference: TreeMap inherits SortedMap and automatically sorts the element's key