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NEW QUESTION: 1
A small but growing software firm is currently subcontracting a call centre to answer its technical support calls. The contact with the agency limits the number of simultaneous tech support calls to 50.
Which vectoring option provides the capability to limit the number of active calls and send the surplus to a busy treatment?
A. expected Wait Time (EWT)
B. Target service level
C. VDN counted calls
D. Activate on oldest call waiting
Answer: C

NEW QUESTION: 2
You are evaluating a Python NumPy array that contains six data points defined as follows:
data = [10, 20, 30, 40, 50, 60]
You must generate the following output by using the k-fold algorithm implantation in the Python Scikit-learn machine learning library:
train: [10 40 50 60], test: [20 30]
train: [20 30 40 60], test: [10 50]
train: [10 20 30 50], test: [40 60]
You need to implement a cross-validation to generate the output.
How should you complete the code segment? To answer, select the appropriate code segment in the dialog box in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

Box 1: k-fold
Box 2: 3
K-Folds cross-validator provides train/test indices to split data in train/test sets. Split dataset into k consecutive folds (without shuffling by default).
The parameter n_splits ( int, default=3) is the number of folds. Must be at least 2.
Box 3: data
Example: Example:
>>>
>>> from sklearn.model_selection import KFold
>>> X = np.array([[1, 2], [3, 4], [1, 2], [3, 4]])
>>> y = np.array([1, 2, 3, 4])
>>> kf = KFold(n_splits=2)
>>> kf.get_n_splits(X)
2
>>> print(kf)
KFold(n_splits=2, random_state=None, shuffle=False)
>>> for train_index, test_index in kf.split(X):
print("TRAIN:", train_index, "TEST:", test_index)
X_train, X_test = X[train_index], X[test_index]
y_train, y_test = y[train_index], y[test_index]
TRAIN: [2 3] TEST: [0 1]
TRAIN: [0 1] TEST: [2 3]
References:
https://scikit-learn.org/stable/modules/generated/sklearn.model_selection.KFold.html

NEW QUESTION: 3
展示を参照してください。

エンジニアは、AS 200を出るすべてのトラフィックがエントリポイントとしてリンク2を選択するようにする必要があります。すべてのBGPネイバー関係が形成されていて、どのルーターでも属性が変更されていないと仮定すると、どの構成でタスクを実行できますか？

A. オプションD
B. オプションB
C. オプションA
D. オプションC
Answer: C
Explanation:
Explanation
R3 advertises BGP updates to R1 with multiple AS 100 so R3 believes the path to reach AS 200 via R3 is farther than R2 so R3 will choose R2 to forward traffic to AS 200.

NEW QUESTION: 4









A. 0
B. 1
C. 2
D. 3
Answer: D