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NEW QUESTION: 1
Nationwide, in one year there were about 21,500 residential fires associated with furniture. Of these,
11,350 were caused by smoking materials. About what percent of the residential fires were smoking- related?
A. 47%
B. 51%
C. 53%
D. 50%
E. 49%
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Division is used to arrive at a decimal, which can then be rounded to the nearest hundredth and converted to a percentage: 11,350 x 21,500 = 0.5279. 0.5279 rounded to the nearest hundredth is 0.53, or 53%.

NEW QUESTION: 2
You enable and configure PowerShell Script Block Logging.
You need to view which script blocks were executed by using Windows PowerShell scripts.
What should you do?
A. Open the log files in %LocalAppData%\\Microsoft\\Windows\\PowerShell.
B. Open the log files in %SYSTEMROOT%\\Logs.
C. View the Microsoft-Windows-PowerShell/Operational event log.
D. View the Windows PowerShell event log.
Answer: C
Explanation:
https://docs.microsoft.com/en-us/powershell/wmf/5.0/audit_scriptAfter you enable detailed script tracing, Windows PowerShell logs all script blocks to the event log,
MicrosoftWindows-PowerShell/Operational.

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:

Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
Answer: A