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NEW QUESTION: 1
In a nonbackbone OSPF area, all traffic that is destined to the Internet is routed by using a default route that is originated by the ABR. Which change in the configuration of the OSPF area type causes traffic from that area that is destined to the Internet to be dropped?
A. The OSPF area changes from stub area to totally stubby area.
B. The OSPF area changes from NSSA to regular area.
C. The OSPF area changes from stub area to NSSA.
D. The OSPF area changes from NSSA to totally stubby area.
Answer: C
Explanation:
The ABR for the NSSA generates the default route, but not by default. To force the ABR to generate the default route, use the area <area id> nssa default-information originate command. The ABR generates a Type 7 LSA with the link-state ID 0.0.0.0 and is advertised inside the NSSA. This default route will be propagated inside the NSSA as Type 7 LSA
Reference: http://www.cisco.com/c/en/us/support/docs/ip/open-shortest-path-first-ospf/1369221.html#nssas

NEW QUESTION: 2
You plan to monitor storage servers after configuring an I/O resource manager plan with directives for inter-database plans and intra-database plans.
Which two types if metrics would help assess the impact of the intra-database plans on I/O to the storage servers?
A. Database I/O
B. Resource Consumer Group I/O
C. Smart Flash Log I/O
D. Category I/O
E. Smart Flash Cache I/O
Answer: A,B
Explanation:
B: Database metrics provide information about the size of the I/O load from each database specified in the interdatabase plan.
C: Consumer group metrics provide information about the size of the I/O load from each consumer group specified in a database resource plan. Each database in the interdatabase plan has metrics for each of its consumer groups.
Note:
* I/O Resource Manager (IROM) Settings
Incorrect:
Not A: Category metrics provide information about the size of the I/O load from each category
specified in the current IORM category plan.

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You administer a Microsoft SQL Server 2008 R2 database that contains an OrderItems table.
The table has the following definition:
CREATE TABLE [OrderItems]
(OrderID INT NOT NULL,
OrderDate DATETIME NOT NULL,
OrderLine INT NOT NULL,
ProductID INT NOT NULL,
Quantity INT NOT NULL,
PriceEach MONEY NOT NULL,
);
Currently, the table is not partitioned and contains no indexes.
You need to partition the table by year.
What should you do?
A. Create a new partition function. Create a new partition scheme. Add a clustered index to place the data onto the partition scheme.
B. Create a new table. Use the ALTER TABLE statement along with the SWITCH PARTITION clause. Use ALTER PARTITION FUNCTION statement along with the MERGE RANGE clause.
C. Use the ALTER TABLE statement to remove the COLLATE option.
D. Run the following statement: EXECUTE sp_tableoption @TableNamePattern ='OrderItems', @OptionName= 'PartitionByYear', @OptionValue= 'true';.
E. Remove the clustered index from the table.
F. Execute the DBCC CLEANTABLE command on the OrderItems table.
G. Use the ALTER PARTITION FUNCTION ... SPLIT RANGE statement.
H. Run the following statement: CREATE PARTITION SCHEME SEC_FG AS PARTITION FUNC_FG ALL TO ( SECONDARY );
I. Create a new Filegroup. Create a new database file. Use the ALTER PARTITION SCHEME statement along with NEXT USED clause Use ALTER PARTITION FUNCTION statement along with the SPLIT RANGE clause
J. Create a new Filegroup. Create a new database file. Use the ALTER PARTITION SCHEME statement along with NEXT USED clause. Use ALTER INDEX REORGANIZE statement.
Answer: A
Explanation:
Original answer was:
Create a new Filegroup.
Create a new database file.
Use the ALTER PARTITION SCHEME statement
Use ALTER INDEX REORGANIZE statement.
Original answer disputed:
From my point of view the best choice is:
Create a new partition function.
Create a new partition scheme.
Add a clustered index to place the data onto the partition scheme.
http://sqlblogcasts.com/blogs/martinbell/archive/2009/07/22/Partitioning-existing-tables.aspx
http://www.kodyaz.com/articles/how-to-partition-table-non-partitioned-table-sql-server-2008.aspx
http://forums.asp.net/t/1581091.aspx/1