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NEW QUESTION: 1
Sie haben eine Datenbank, die sowohl festplattenbasierte als auch speicheroptimierte Tabellen enthält.
Sie müssen zwei Module erstellen. Die Module müssen die in der folgenden Tabelle beschriebenen Anforderungen erfüllen.

Welches Programmierobjekt sollten Sie für jedes Modul verwenden? Wählen Sie zum Beantworten die entsprechenden Objekttypen im Antwortbereich aus.

Answer:
Explanation:

Erläuterung

Modul 1: Interpretierte gespeicherte Prozedur
Eine interpretierte gespeicherte Prozedur kann auf festplattenbasierte und speicheroptimierte Tabellen zugreifen.
Modul 2: Nativ kompilierte gespeicherte Prozedur
Nativ kompilierte gespeicherte Prozeduren sind gespeicherte Transact-SQL-Prozeduren, die zu nativem Code kompiliert wurden, um auf speicheroptimierte Tabellen zuzugreifen. Nativ kompilierte gespeicherte Prozeduren ermöglichen eine effiziente Ausführung der Abfragen und der Geschäftslogik in der gespeicherten Prozedur.
Verweise:
https://docs.microsoft.com/de-de/sql/relational-databases/in-memory-oltp/nativ-compiled-stored-procedures?v

NEW QUESTION: 2

A. Option C
B. Option B
C. Option E
D. Option A
E. Option D
Answer: A,D
Explanation:
A:Assembly versions are everywhere in SharePoint - web.config files, web
part definitions, workflow definitions, event receiver bindings - the list goes on. In each
case, the version number is absolutely required so that SharePoint can load the code to
run at that time. If you update an assembly's version, you have two choices to ensure your
code can still be loaded:
/ Find and update every reference to the previous assembly version.
/ Use a binding redirect in the relevant .config file (e.g. web.config) to point to the new
version of the assembly.
C: Assembly Version : This is the version number used by framework during build and at runtime to locate, link and load the assemblies. When you add reference to any assembly in your project, it is this version number which gets embedded. At runtime, CLR looks for assembly with this version number to load. But remember this version is used along with name, public key token and culture information only if the assemblies are strong-named signed. If assemblies are not strong-named signed, only file names are used for loading.
Incorrect:
not B: Assembly File Version : This is the version number given to file as in file system. It is
displayed by Windows Explorer. Its never used by .NET framework or runtime for
referencing.
From scenario:
*solution artifacts must adhere to industry best practices.
*Code based hot fixes must be deployed directly to the Global Assembly Cache on all SharePoint servers.
*Only one version of an assembly must be available at runtime.

NEW QUESTION: 3
A sys admin is trying to understand the sticky session algorithm. Please select the correct sequence of steps, both when the cookie is present and when it is not, to help the admin understand the implementation of the sticky session:
ELB inserts the cookie in the response
ELB chooses the instance based on the load balancing algorithm
Check the cookie in the service request
The cookie is found in the request
The cookie is not found in the request
A. 3,2,5,4 [Cookie is not Present] & 3,2,4,5 [Cookie is Present]
B. 3,1,4,2 [Cookie is not Present] & 3,1,5,2 [Cookie is Present]
C. 3,5,2,1 [Cookie is not Present] & 3,4,2,1 [Cookie is Present]
D. 3,4,1,2 [Cookie is not Present] & 3,5,1,2 [Cookie is Present]
Answer: C
Explanation:
Explanation
Generally AWS ELB routes each request to a zone with the minimum load. The Elastic Load Balancer provides a feature called sticky session which binds the user's session with a specific EC2 instance. The load balancer uses a special load-balancer-generated cookie to track the application instance for each request. When the load balancer receives a request, it first checks to see if this cookie is present in the request. If so, the request is sent to the application instance specified in the cookie. If there is no cookie, the load balancer chooses an application instance based on the existing load balancing algorithm. A cookie is inserted into the response for binding subsequent requests from the same user to that application instance.

NEW QUESTION: 4
Ferris Plastics, Inc. is a medium sized company, with an enterprise network (access, distribution and core switches) that provides LAN connectivity from user PCs to corporate servers. The distribution switches are configured to use HSRP to provide a high availability solution.
DSW1 -primary device for VLAN 101 VLAN 102 and VLAN 105
DSW2 - primary device for VLAN 103 and VLAN 104
A failure of GigabitEthemet1/0/1 on primary device should cause the primary device to release its status as the primary device, unless GigabitEthernet1/0/1 on backup device has also failed.
Troubleshooting has identified several issues. Currently all interfaces are up. Using the running configurations and show commands, you have been asked to investigate and respond to the following question.


During routine maintenance, it became necessary to shut down the GigabitEthernet1/0/1 interface on DSW1 and DSW2. All other interfaces were up. During this time, DSW1 became the active router for the VLAN 104HSRP group. As related to the VLAN 104HSRP group, what can to be done to make the group function properly?
A. On DSW1, increase the decrement value in the track command to a value greater than 6.
B. On DSW1, disable preempt.
C. On DSW1, decrease the decrement value in the track command to a value less than 1.
D. On DSW2 decrease the priority value to a value less than 150.
Answer: A
Explanation:

http://dc342.4shared.com/doc/UoRbVi9j/preview_html_468b453a.jpg We should NOT disable preempt on DS1. By do that, you will make Vlan104's HSRP group fail function. Example: if we are disable preempt on DS1. It can not become active device when G1/0/1 on DS2 fail. In this question, G0/1/0 on DS1 &DS2 is shutdown. Vlan104 (left):150 - 1 = 149. Vlan104 (right): 200 - 155 = 145. Result is priority 149 > 145 (Vlan104 on DS1 is active). If increase the decrement in the track value to a value greater than 6 (> or = 6). Vlan104 (left): 150 - 6 = 144. Result is priority 144 < 145 (vlan104 on DS2 is active).