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NEW QUESTION: 1
EIGRPv6を有効にするには、どの機能または値を構成する必要がありますか？
A. ネットワークステートメント
B. シャットダウン機能
C. リモートAS
D. ルーターID
Answer: D
Explanation:
EIGRP for IPv6の構成にはいくつかの制限があります。次のとおりです。
インターフェイスは、グローバルIPv6アドレスを使用せずに、EIGRP for IPv6で直接構成できます。
EIGRP for IPv6にはネットワークステートメントはありません。
ルーターIDは、EIGRPv6プロトコルインスタンスを実行する前に構成する必要があります。
EIGRP for IPv6にはシャットダウン機能があります。プロトコルを実行するには、ルーティングプロセスが「no shut」モードになっていることを確認してください。
https://www.cisco.com/c/en/us/support/docs/ip/enhanced-interior-gateway-routing-protocol- eigrp / 113267-eigrp-ipv6-00.html

NEW QUESTION: 2
Which of the following is a KEY consideration to ensure the availability of nodes in an active-active application cluster configuration?
A. Adequate storage exists across all nodes.
B. Some of the nodes are located in the same city.
C. Network encryption exists between nodes
D. The duster agent software used is open source
Answer: C

NEW QUESTION: 3
リスクはリスク評価中に特定されました。ビジネスプロセスの所有者がリスクを受け入れることを選択したのは、修正のコストが最悪のシナリオの予測コストよりも大きいためです。情報セキュリティ管理者の次の行動方針は何ですか？
A. 問題を再検討する日付を文書化してスケジュールします。
B. 修正のための低コストのアプローチを決定します。
C. 文書化し、上級管理職にエスカレーションします。
D. ビジネスアプリケーションをシャットダウンします。
Answer: C

NEW QUESTION: 4
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)

You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format.

Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers=CustomerId = 1 FOR XML RAW, ELEMENTS
B. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
D. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
E. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
F. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW
G. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
H. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
Answer: C
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms188273.aspx