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NEW QUESTION: 1
Ann, a software developer, has installed some code to reactivate her account one week after her account has been disabled. Which of the following is this an example of? (Choose two.)
A. Backdoor
B. Rootkit
C. Logic Bomb
D. Spyware
E. Botnet
Answer: A,C
Explanation:
Explanation/Reference:
Explanation:
This is an example of both a logic bomb and a backdoor. The logic bomb is configured to 'go off' or activate one week after her account has been disabled. The reactivated account will provide a backdoor into the system.
A logic bomb is a piece of code intentionally inserted into a software system that will set off a malicious function when specified conditions are met. For example, a programmer may hide a piece of code that starts deleting files should they ever be terminated from the company.
Software that is inherently malicious, such as viruses and worms, often contain logic bombs that execute a certain payload at a pre-defined time or when some other condition is met. This technique can be used by a virus or worm to gain momentum and spread before being noticed. Some viruses attack their host systems on specific dates, such as Friday the 13th or April Fool's Day. Trojans that activate on certain dates are often called "time bombs".
To be considered a logic bomb, the payload should be unwanted and unknown to the user of the software.
As an example, trial programs with code that disables certain functionality after a set time are not normally regarded as logic bombs.
A backdoor in a computer system (or cryptosystem or algorithm) is a method of bypassing normal authentication, securing unauthorized remote access to a computer, obtaining access to plaintext, and so on, while attempting to remain undetected. The backdoor may take the form of an installed program (e.g., Back Orifice) or may subvert the system through a rootkit.
A backdoor in a login system might take the form of a hard coded user and password combination which gives access to the system.

NEW QUESTION: 2
Which of the following statements are true:
I. Credit risk and counterparty risk are synonymous
II. Counterparty risk is the contingent risk from a counterparty's default in derivative transactions III. Counterparty risk is the risk of a loan default or the risk from moneys lent directly IV. The exposure at default is difficult to estimate for credit risk as it depends upon market movements
A. III and IV
B. II
C. I and II
D. II and III
Answer: B
Explanation:
Explanation
Credit risk is the risk from a borrower defaulting on moneys lent. Counterparty risk, on the other hand, is the risk that a counterparty to a derivative transaction will be unable to pay at the time the transaction is in-the-money.
Credit risk therefore relates more to the banking book, counterparty risk relates more to the trading book.
Credit risk and counterparty risk differ in that for counterparty risk, the amount at risk fluctuates for counterparty risk depending upon the value of the underlying derivative. Counterparty risk generally starts at zero, for most swaps and other derivatives are near zero value at inception. Over time, as the prices of the underlying instruments move, one party ends up owing money to the other. A deterioration in the financial situation of the party owing moneys may lead to a loss to the other party, resulting in counterparty risk.
Counterparty risk can also arise from stock lending operations and repo trades.
Credit risk on the other hand is the traditional risk of default by a borrower, or a bank's customer who has taken a loan or has an overdraft or other credit facility.
Statement I is therefore incorrect as credit risk and counterparty risks are different.
Statement II is correct as counterparty risk is 'contingent' in the sense it arises only if the transaction with the counterparty ends up being in-the-money, and the counterparty defaults.
Statement III is incorrect. The statement describes credit risk.
Statement IV is incorrect, as the exposure is known for moneys lent. Derivative exposures for the future are difficult to estimate, they can even turn from moneys owed to moneys due as the value of the underlying changes.

NEW QUESTION: 3
API統合パターンは、どのユースケースを有効にするために使用されますか？
A. クローズドヘリテージシステムまたは異種バックエンドのサービスへの非同期ポイントツーポイントアクセス
B. さまざまなバックエンドにわたるきめ細かいサービスへの同期アクセス
C. マルチクラウドおよびオンプレミスのコンテキスト間でのサービスの非同期多対多調整
D. クローズドヘリテージシステムまたは異種バックエンドのサービスへの同期ポイントツーポイントアクセス
Answer: A

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
B operator +(const B &b )const { return B(val + b.val);} };
ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out { ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out<<val<<" "; } }; template<typename A> struct Add : public binary_function<A, A, A> { A operator() (const A & a, const A & b) const { return a+b; }}; int main() { int t[]={1,2,3,4,5,6,7,8,9,10}; vector<B> v1(t, t+10); vector<B> v2(10); transform(v1.begin(), v1.end(), v2.begin(), bind1st(ptr_fun (Add<B>()), 1)); for_each(v2.rbegin(), v2.rend(), Out<B>(cout));cout<<endl; return 0;
}
Program outputs:
A. 2 3 4 5 6 7 8 9 10 11
B. 10 9 8 7 6 5 4 3 2 1
C. 1 2 3 4 5 6 7 8 9 10
D. compilation error
E. 11 10 9 8 7 6 5 4 3 2
Answer: D