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NEW QUESTION: 1
과거에 사내 구축 환경에서 전용 데이터 그룹을 사용하여이 데이터를 처리하고 Rabbit MQAn 오픈 소스 메시징 시스템을 사용하여 서버. 일단 데이터가 처리되면 오프 사이트로 출고됩니다. 관리자는 현재 디자인을 유지하고 비용을 최소화하기 위해 AWS 보관 저장 및 메시징 서비스를 활용하라고했습니다. 어느 것이 맞습니까?
A. SNS를 사용하여 작업 메시지를 전달하면 클라우드 감시 알람을 사용하여 현장 작업자 인스턴스가 유휴 상태가 될 때 종료합니다. 데이터가 처리되면 53 개체의 저장소 클래스를 Glacier로 변경합니다.
B. 작업 메시지 전달을 위해 SQS를 사용하면 클라우드 감시 알람을 사용하여 EC2 작업자 인스턴스가 유휴 상태가 될 때 종료합니다. 데이터가 처리되면 53 개체의 저장소 클래스를 Redundancy Redundancy Storage로 변경합니다.
C. SOS에서 메시지를 처리하기 위해 스팟 인스턴스를 사용하는 대기열 깊이에 의해 트리거 된 자동 확장 작업자 설정 데이터가 처리되면,
D. 53 개 개체의 저장소 클래스를 Redundancy Redundancy Storage로 변경합니다. 공간 인스턴스를 사용하여 SQS의 메시지를 처리하는 대기열 깊이에 의해 트리거 된 자동 확장 작업자 설정 데이터가 처리되면 53 개체의 저장 클래스를 빙하로 변경합니다.
Answer: A

NEW QUESTION: 2
Assume that 40% of all financial organizations investigated by authorities turn out to be fraudulent.
What is the probability of randomly investigating 2 different organizations and finding that neither is fraudulent; and what is the probability of finding exactly one being fraudulent?
A. 1/3 and 8/17
B. 2/5 and 3/5
C. 2/5 and 1/2
D. 9/25 and 12/25
Answer: D

NEW QUESTION: 3
継続的な情報セキュリティ監視プログラムは、以下のいずれかのリスクを最小限に抑えることができますか？
A. スケジュールされたシステム変更とスケジュールされていないシステム変更の両方のロギング
B. 重要なユーザーアカウントの活動に対するシステム全体の可視性の促進
C. セキュリティイベントを収集し、それらを相関させて異常を特定する
D. 人々、プロセス、技術を包含する
Answer: D

NEW QUESTION: 4
Refer to the exhibit. In this network, R1 has been configured to advertise a summary route, 192.168.0.0/22, to R2. R2 has been configured to advertise a summary route, 192.168.0.0/21, to R1. Both routers have been configured to remove the discard route (the route to null created when
a summary route is configured) by setting the administrative distance of the discard route to 255. What will happen if R1 receives a packet destined to 192.168.3.1 ?

A. The packet will loop between R1 and R2.
B. The packet will be dropped by R1, since there is no route to 192.168.3.1.
C. It is not possible to set the administrative distance on a summary to 255.
D. The packet will be forwarded to R2, where it will be routed to null0.
Answer: A
Explanation:
Indeed, when you change the administrative distance of the discard route to 255, this prevents the
route to be installed in the routing table but this does not prevent the route to be advertised to the
other peer!
From the Cisco website:
"You can configure a summary aggregate address for a specified interface. If there are any more
specific routes in the routing table, EIGRP will advertise the summary address out the interface
with a metric equal to the minimum of all more specific routes"
And don't forget YOU HAVE a directly connected route 192.168.1/24 in R1 and .4/24 in R2.
Then your summary is advertised, and the packet loop between R1 and R2.
If you do the test with GNS3, you will see via "show ip eigrp topology" that you FD of your local
subnet 192.168.1.0/24 in R1 become the metric of the summary route "192.168.0.0/22 advertise to
R2 ! And viceversa. Numerically, an administrative distance is an integer from 0 to 255. In general,
the higher the value, the lower the trust rating. An administrative distance of 255 means that the
routing information source cannot be trusted at all and should be ignored.
http://www.cisco.com/en/US/docs/ios/12_3/iproute/command/reference/ip2_c1g.html
A route with an AD of 255 would never be installed in the RIB. It is much better for the router to
forward a packet to null0 following the default route than for the router to find out it has no route to destination, drop the packet and probably to send an ICMP unreachable message back to the source of that packet.
https://supportforums.cisco.com/thread/192416 You should not use the ip summary-address eigrp summarization command to generate the default route (0.0.0.0) from an interface. This causes the creation of an EIGRP summary default route to the null 0 interface with an administrative distance of 5. The low administrative distance of this default route can cause this route to displace default routes learned from other neighbors from the routing table. If the default route learned from the neighbors is displaced by the summary default route, or if the summary route is the only default route present, all traffic destined for the default route will not leave the router, instead, this traffic will be sent to the null 0 interface where it is dropped.
http://www.cisco.com/en/US/docs/ios/12_0/np1/configuration/guide/1ceigrp.html#wp4937

Here are the configurations and CLI output to prove the answer is A.
This is done on IOS 12.4T train of code.
R1
interface Loopback0 ip address 192.168.1.1 255.255.255.0 ! interface FastEthernet0/0 ip address 10.1.2.1 255.255.255.0 ip summary-address eigrp 1 192.168.0.0 255.255.252.0 255
! router eigrp 1 network 10.0.0.0 network 192.168.1.0 no auto-summary R2
interface Loopback0 ip address 192.168.4.2 255.255.255.0 ! interface FastEthernet0/0 ip address 10.1.2.2 255.255.255.0 ip summary-address eigrp 1 192.168.0.0 255.255.248.0 255 ! router eigrp 1 network 10.0.0.0 network 192.168.4.0 no auto-summary Show Output
Look at R1 s routing table...notice it does NOT have the summary route to null0 for 192.168.0.0/22 because we have disabled it. It does have a summary route to 192.168.0.0/21 from R2 it is receiving... R1#show ip route | b Gateway Gateway of last resort is not set 10.0.0.0/24 is subnetted, 1 subnets C 10.1.2.0 is directly connected, FastEthernet0/0 C 192.168.1.0/24 is directly connected, Loopback0 D 192.168.0.0/21 [90/156160] via 10.1.2.2, 00:03:45, FastEthernet0/0 Now look at R2 s routing table. Notice it does NOT have a summary route to null0 for the 192.168.0.0/21 because we disabled it. It does however have a route for 192.168.0.0/22 received from R1. R2#sh ip route | b Gateway Gateway of last resort is not set C 192.168.4.0/24 is directly connected, Loopback0 10.0.0.0/24 is subnetted, 1 subnets C 10.1.2.0 is directly connected, FastEthernet0/0 D 192.168.0.0/22 [90/156160] via 10.1.2.1, 00:05:36, FastEthernet0/0 Now, what will happen? As I said -- When R1 pings 192.168.3.1 it will look in its routing table, and it will see the
EIGRP route 192.168.0.0/21 from R2 so it will send the packet to R2 since 192.168.3.1 is part of
that summary.
R2 will get the packet and look in its routing table. It will find an EIGRP route for 192.168.0.0/22
from R1 and route the packet back to R1 since 192.168.3.1 is within that summary range.
This continues in a loop until the IP TTL expires.
Traceroute from R1. Notice it goes to R2 then right back to R1...Hope this helps! ----------------
R1#trace 192.168.3.1
Type escape sequence to abort.
Tracing the route to 192.168.3.1
1 10.1.2.2 0 msec 0 msec 4 msec
2 10.1.2.1 0 msec 0 msec 4 msec 3 * * *