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NEW QUESTION: 1
HOTSPOT
Extract from the Project Product Description (with errors)

The information in Column 1 may be entered in the Product Description for the chosen label design. Column 2 is a list of the quality headings (excluding Quality Method) in a Product Description. For each entry in Column 1 decide if it should be included in the Product Description headings shown and select the heading from Column 2 under which it should be recorded.
Drop down the right answer


Answer:
Explanation:

NEW QUESTION: 2
You are asked to design a Layer 2 VPN service for a service provider network that supports Ethernet and ATM transport. Which two Layer 2 VPN technologies will meet this requirement? (Choose two.)
A. BGP Layer 2 VPN, using draft-Martini encapsulation
B. BGP-signaled VPLS, using the RFC 4448 Layer 2 frame format
C. LDP Layer 2 circuit, using the RFC 4448 Layer 2 frame format
D. LDP-signaled VPLS, using draft martini encapsulation
Answer: A,C

NEW QUESTION: 3
Examine the structure of the EMPLOYEEStable.
Name Null? Type
- ---------------- ----- ------ ------
EMPLOYEE_ID NOT NULL NUMBER(6)
FIRST_NAME VARCHAR2(20)
LAST_NAME NOT NULL VARCHAR2(25)
EMAIL NOT NULL VARCHAR2(25)
PHONE NUMBER VARCHAR2(20)
HIRE_DATE NOT NULL DATE
JOB_ID NOT NULL VARCHAR2(10)
SALARY NUMBER(8,2)
COMMISSION_PCT NUMBER(2,2)
MANAGER_ID NUMBER(6)
DEPARTMENT_ID NUMBER(4)
There is a parent/child relationship between EMPLOYEE_IDand MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_IDis 123.
Which query provides the correct output?
A. SELECT e.last_name, m.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.manager_id = m.employee_id)
AND e.employee_id = 123;
B. SELECT e.last_name, e.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.employee_id = m.employee_id)
WHERE e.employee_id = 123;
C. SELECT m.last_name, e.manager_id
FROM employees e LEFT OUTER JOIN employees m
on (e.manager_id = m.manager_id)
WHERE e.employee_id = 123;
D. SELECT e.last_name, m.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.employee_id = m.manager_id)
WHERE e.employee_id = 123;
Answer: D