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NEW QUESTION: 1
Which command will allow you to collect all facts for the specific host group 'labmachines'?
A. ansible labmachines -m setup
B. ansible -c setup labmachines
C. ansible labmachines -m facts
D. ansible-gather-facts labmachines
Answer: A
Explanation:
This command specifies the correct inventory and uses the setup module which gathers facts for target hosts.

NEW QUESTION: 2
Ihr Netzwerk enthält eine Active Directory-Domäne, die mit Microsoft Azure Active Directory (Azure AD) synchronisiert ist. Die Domäne enthält 500 Laptops, auf denen Windows 8.1 Professional ausgeführt wird. Die Benutzer der Laptops arbeiten von zu Hause aus.
Ihr Unternehmen verwendet Microsoft Intune, das Microsoft Deployment Toolkit (MDT) und Windows Configuration Designer zum Verwalten von Clientcomputern.
Das Unternehmen erwirbt 500 Lizenzen für Windows 10 Enterprise.
Sie überprüfen, ob die Hardware und Anwendungen auf den Laptops mit Windows 10 kompatibel sind.
Die Benutzer bringen ihren Laptop ins Büro, wo die IT-Abteilung Windows 10 auf den Laptops bereitstellt, während die Benutzer warten.
Sie müssen eine Bereitstellungsmethode für die Laptops empfehlen, bei der die installierten Anwendungen beibehalten werden. Die Lösung muss minimieren, wie lange es dauert, die Bereitstellung durchzuführen.
Was sollten Sie in die Empfehlung aufnehmen?
A. Eine Neuinstallation mithilfe eines Windows Configuration Designer-Bereitstellungspakets
B. eine Neuinstallation und das User State Migration Tool (USMT)
C. ein direktes Upgrade
D. Windows AutoPilot
Answer: C
Explanation:
References:
https://docs.microsoft.com/en-us/windows/deployment/windows-10-deployment-scenarios#in-place-upgrade

NEW QUESTION: 3



A. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY c.CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
Where o.Rnk = 1
C. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName,
o. ShippingCountry,
RANK() OVER (PARTITION BY c. CustomerID
ORDER BY o. OrderAmount DESC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WHERE Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
Answer: C

NEW QUESTION: 4

A. Option D
B. Option C
C. Option A
D. Option B
Answer: C,D