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NEW QUESTION: 1

A. Reset-PhysicalDisk -FriendlyName Disk3
B. Set-ResiliencySetting -StoragePool Pool1 -PhysicalDiskRedundancyDefault 4
C. Update-StoragePool -FriendlyName Pool1
D. Set-PhysicalDisk -FriendlyName Disk3 -Usage Retired
E. Remove-PhysicalDisk -FriendlyName Disk3
Answer: D,E
Explanation:
Explanation:

NEW QUESTION: 2
Note: This question is part of a series of questions that present the same scenario. Each question in the series contains a unique solution that might meet the stated goals. Some question sets might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this sections, you will NOT be able to return to it. As a result, these questions will not appear in the review screen.
Your network contains an Active Directory domain named contoso.com. The domain contains a DHCP server named Server2 than runs Windows Server 2016.
Users report that their client computers fail to obtain an IP address.
You open the DHCP console as shown in the Exhibit. (Click the Exhibit button.)

Scope1 has an address range of 172.16.0.10 to 172.16.0.100 and a prefix length of 23 bits.
You need to ensure that all of the client computers on the network can obtain an IP address from Server2.
Solution: You run the Set-DhcpServerv4MulticastScope
Does this meet the goal?
A. Yes
B. No
Answer: B

NEW QUESTION: 3
Given the fragment:
String[][] arra = new String[3][];
arra[0] = new String[]{"rose", "lily"};
arra[1] = new String[]{"apple", "berry","cherry","grapes"};
arra[0] = new String[]{"beans", "carrot","potato"};
// insert code fragment here
Which code fragment when inserted at line '// insert code fragment here', enables the code to successfully change arra elements to uppercase?
A. for (int i = 0; i < 3; i++) {
for (int j=0; j < 4; j++) {
arra[i][j] = arra[i][j].toUpperCase();
}
}
B. for (String a[]:arra[][]) {
for (String x:a[]) {
C. String[][] arra = new String[3][];
arra[0] = new String[]{"rose", "lily"};
arra[1] = new String[]{"apple", "berry","cherry","grapes"};
arra[0] = new String[]{"beans", "carrot","potato"};
for (int i = 0; i < arra.length; i++) {
for (int j=0; j < arra[i].length; j++) {
arra[i][j] = arra[i][j].toUpperCase();
}
}
D. toUpperCase();
}
}
E. for (int i:arra.length) {
for (String x:arra) {
arra[i].toUpperCase();
}
}
Answer: B
Explanation:
Incorrect:
not A:arra.lengthis 3, but the subarrays have 2, 3 and 4 elements. Index will be out of bound.
not B: The subarrys are of different lengths.Index will be out of bound.
not D: Compile error.