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NEW QUESTION: 1

A. Option D
B. Option C
C. Option B
D. Option A
Answer: D

NEW QUESTION: 2
Ein Benutzer hat die Sicherungslasche eines Netzwerkkabels gelöst. Welches der folgenden Werkzeuge würde Jeff, ein Techniker, verwenden, um den RJ-45-Stecker zu ersetzen?
A. Kabeltester
B. Multimeter
C. Schlag runter
D. Crimper
Answer: D

NEW QUESTION: 3
モバイルゲームを開発している会社は、2つのAWSリージョンでゲームアセットを利用できるようにしています。ゲームアセットは、各リージョンのApplication Load Balancer（ALB）の背後にある一連のAmazonEC2インスタンスから提供されます。同社は、ゲームアセットを最も近い地域から取得することを要求しています。ゲームアセットが最も近いリージョンで利用できなくなった場合は、他のリージョンからフェッチする必要があります。
これらの要件を満たすために、ソリューションアーキテクトは何をすべきですか？
A. ALBごとにAmazon Route53ヘルスチェックを作成します。 2つのALBを指すRoute53レイテンシーエイリアスレコードを作成します。 Evaluate TargetHealthの値をYesに設定します。
B. AmazonCloudFrontディストリビューションを作成します。 ALBごとに1つのオリジンを持つオリジングループを作成します。原点の1つをプライマリとして設定します。
C. ALBごとにAmazon Route53ヘルスチェックを作成します。 2つのALBを指すRoute53フェールオーバールーティングレコードを作成します。 Evaluate TargetHealthの値をYesに設定します。
D. それぞれがオリジンとして1つのALBを持つ2つのAmazonCloudFrontディストリビューションを作成します。 2つのCloudFrontディストリビューションを指すAmazonRoute53フェイルオーバールーティングレコードを作成します。 Evaluate TargetHealthの値をYesに設定します。
Answer: A

NEW QUESTION: 4
Given: In XYZ's small business, two autonomous 802.11ac APs and 12 client devices are in use with WPA2-Personal.
What statement about the WLAN security of this company is true?
A. An unauthorized WLAN user with a protocol analyzer can decode data frames of authorized users if he captures the BSSID, client MAC address, and a user's 4-Way Handshake.
B. Because WPA2-Personal uses Open System authentication followed by a 4-Way Handshake, hijacking attacks are easily performed.
C. An unauthorized wireless client device cannot associate, but can eavesdrop on some data because WPA2-Personal does not encrypt multicast or broadcast traffic.
D. A successful attack against all unicast traffic on the network would require a weak passphrase dictionary attack and the capture of the latest 4-Way Handshake for each client.
E. Intruders may obtain the passphrase with an offline dictionary attack and gain network access, but will be unable to decrypt the data traffic of other users.
Answer: D